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question:You are given a list of n non-negative integers representing the amount of money in each bank. You need to calculate the minimum number of operations required to equalize all banks' amounts, where an operation consists of picking any two banks, and incrementing or decrementing the amount of money in one of the banks by 1. Input: - The first line of input contains the integer n (1 ≤ n ≤ 1000), the number of banks. - The second line of input contains n non-negative integers separated by spaces, representing the amount of money in each bank. Each integer is guaranteed to be ≤ 10^6. Output: - Output a single integer, the minimum number of operations required to equalize all banks' amounts. Example: Input 4 1 3 2 4 Output 2 Explanation: To equalize all banks, you can: 1. Increment the amount in the first bank by 1 (now the amounts are [2, 3, 2, 4]) 2. Decrement the amount in the fourth bank by 1 (now the amounts are [2, 3, 2, 3]) 3. Increment the amount in the first bank by 1 and decrement the amount in the second bank by 1 simultaneously (now the amounts are [3, 2, 3, 3]) 4. Increment the amount in the second bank by 1 and decrement the amount in the third bank by 1 (now all amounts are [3, 3, 3, 3]) So the minimum number of operations required is 2. Note: - You can pick any two banks in each operation. - The answer will be guaranteed to fit within a 32-bit signed integer.
answer:def min_operations_to_equalize(banks): Given a list of non-negative integers representing the amount of money in each bank, calculate the minimum number of operations required to equalize all banks' amounts. An operation consists of picking any two banks and incrementing the amount of money in one of the banks by 1 and decrementing the amount in the other bank by 1. Args: banks: List[int] - a list of non-negative integers representing the amount of money in each bank Returns: int - the minimum number of operations required to equalize all banks' amounts total_money = sum(banks) n = len(banks) mean_value = total_money // n operations = 0 for money in banks: operations += abs(money - mean_value) return operations // 2
question:You are given an array of integers `arr` representing the heights of a series of buildings. The buildings are situated in such a way that they form a skyline with some peaks and valleys. Your task is to determine the total volume of water that can be trapped between the buildings after it rains. The water trapped at any position is determined by the height of the buildings to the left and right of that position. Write a function `trap_water(arr)` that takes a list of non-negative integers and returns the total volume of water trapped. # Input - A single list of integers `arr` where `1 <= len(arr) <= 10000` and `0 <= arr[i] <= 1000`. # Output - An integer representing the total volume of water trapped. # Example Input ``` [0,1,0,2,1,0,1,3,2,1,2,1] ``` Output ``` 6 ``` Explanation - In the given example, 6 units of water can be trapped between the buildings. # Example Input ``` [4,2,0,3,2,5] ``` Output ``` 9 ``` Explanation - In the given example, 9 units of water can be trapped between the buildings. # Note - The problem consists of finding the water above each building by calculating the minimum of the maximum heights to the left and right at each building's position, then subtracting the building's own height from this value. By summing up these individual values, you get the total water trapped.
answer:def trap_water(arr): if not arr: return 0 n = len(arr) left_max = [0] * n right_max = [0] * n left_max[0] = arr[0] for i in range(1, n): left_max[i] = max(left_max[i-1], arr[i]) right_max[n-1] = arr[n-1] for i in range(n-2, -1, -1): right_max[i] = max(right_max[i+1], arr[i]) total_water = 0 for i in range(n): total_water += min(left_max[i], right_max[i]) - arr[i] return total_water
question:You are given a string representing a sequence of moves: 'L' (left), 'R' (right), 'U' (up) and 'D' (down). You start at the origin point (0, 0) on a 2D plane and follow the sequence of moves. Your task is to determine whether you end up back at the origin (0, 0) after completing all the moves in the sequence. Input A single string s consisting of characters 'L', 'R', 'U', and 'D'. The length of the string does not exceed 100,000. Output Print "Yes" (without the quotes) if you end up back at the origin after all the moves, or "No" (without the quotes) otherwise. Examples Input LLRR Output Yes Input UDDLLRUU Output No Input UDLR Output Yes Note In the first example, the sequence of moves "LLRR" moves 2 steps to the left and 2 steps to the right, which brings you back to the origin. In the second example, the sequence of moves "UDDLLRUU" does not bring you back to the origin, as it results in a final position that is not (0, 0). In the third example, the sequence of moves "UDLR" brings you back to the origin as it results in a position of (0, 0).
answer:def is_back_to_origin(s): Determine if the sequence of moves brings you back to the origin (0, 0). x, y = 0, 0 for move in s: if move == 'L': x -= 1 elif move == 'R': x += 1 elif move == 'U': y += 1 elif move == 'D': y -= 1 return "Yes" if (x == 0 and y == 0) else "No"
question:Given a string s, you are tasked with analyzing the string to determine the minimum number of contiguous substrings you can split the string into such that each substring contains only unique characters. -----Input----- The only line of input contains a string s (1 ≤ |s| ≤ 10^5) consisting of lowercase English letters. -----Output----- Output a single integer representing the minimum number of contiguous substrings. -----Examples----- Input abac Output 2 Input aaaaaa Output 6 -----Note----- In the first sample, the string "abac" can be split into two substrings "ab" and "ac", where each substring has unique characters. In the second sample, each character in the string "aaaaaa" must be in its own substring as each character is the same.
answer:def min_unique_substrings(s): Returns the minimum number of contiguous substrings such that each substring contains only unique characters. substrings = 1 seen_chars = set() for char in s: if char in seen_chars: substrings += 1 seen_chars = set(char) else: seen_chars.add(char) return substrings