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question:A gaming tournament is being held where each player competes in multiple rounds. At the end of the tournament, each player’s highest score from any round is considered as their final score. You are provided with the scores of N players over M rounds. Your task is to determine the final score for each player. ------ Input Format ------ - The first line of input contains two integers, N (number of players) and M (number of rounds). - The next N lines contain M integers each, representing the scores of a player in each round. ------ Output Format ------ For each player, output their final score (the highest score achieved in any round). ------ Constraints ------ 1 ≤ N ≤ 100 1 ≤ M ≤ 100 0 ≤ score le 10000 ----- Sample Input 1 ------ 3 4 10 35 20 15 40 20 50 30 25 30 20 40 ----- Sample Output 1 ------ 35 50 40 ----- Explanation 1 ------ Player 1 scores: [10, 35, 20, 15] => Highest score: 35 Player 2 scores: [40, 20, 50, 30] => Highest score: 50 Player 3 scores: [25, 30, 20, 40] => Highest score: 40
answer:def final_scores(n, m, scores): Determines the final score for each player. :param n: Number of players :param m: Number of rounds :param scores: List of scores for each player in each round :return: List of final scores for each player final_scores = [] for player_scores in scores: final_scores.append(max(player_scores)) return final_scores
question:Given an integer array `arr` and a number of operations `q`. In each operation, you are given two indices `l` and `r` (1-based) and a value `val`. You need to add `val` to every element in the subarray from index `l` to index `r` (inclusive) and then return the sum of all elements in the array. The task is to perform all the operations efficiently and return the resulting sums for each operation. Input The first line contains two integers `n` (1 ≤ n ≤ 100,000) and `q` (1 ≤ q ≤ 100,000) representing the size of the array and the number of operations respectively. The second line contains `n` space-separated integers representing the initial elements of the array. Each of the next `q` lines contains three space-separated integers `l`, `r`, and `val` describing an operation. Output For each operation, output a single line containing the sum of the array after performing the operation. Example Input: 5 3 1 2 3 4 5 1 3 10 2 5 -3 3 3 5 Output: 40 37 37 Explanation: Initial array: [1, 2, 3, 4, 5] After 1st operation: [11, 12, 13, 4, 5], sum = 11+12+13+4+5 = 45 After 2nd operation: [11, 9, 10, 1, 2], sum = 11+9+10+1+2 = 33 After 3rd operation: [11, 9, 15, 1, 2], sum = 11+9+15+1+2 = 38
answer:def perform_operations(n, q, arr, operations): Perform operations on the array and return the sum of the array after each operation. results = [] for op in operations: l, r, val = op for i in range(l-1, r): # Convert to 0-based index arr[i] += val results.append(sum(arr)) return results
question:You are given a list of integers and a target sum. Your task is to determine if there are two distinct integers in the list that add up to the target sum. If such a pair exists, return `True`; otherwise, return `False`. **Input:** - An integer `n`, the number of elements in the list. - A list of `n` integers. - An integer `target`, the target sum. **Output:** - A boolean value (`True` or `False`). **Example:** SAMPLE INPUT: 5 [2, 7, 11, 15, 1] 9 SAMPLE OUTPUT: True Explanation: For the given list [2, 7, 11, 15, 1] and target sum 9, the pair of integers (2, 7) sums up to the target sum 9. Thus, the output is `True`.
answer:def has_two_sum(n, numbers, target): Determines if there are two distinct integers in the list that add up to the target sum. Args: n (int): Number of elements in the list. numbers (list): List of integers. target (int): Target sum. Returns: bool: True if there are two distinct integers that add up to the target sum, False otherwise. seen = set() for num in numbers: if target - num in seen: return True seen.add(num) return False
question:Design a system that handles efficient querying and updates on a dynamic list of numbers. Specifically, you should implement a class `DynamicRangeSum` which supports the following operations: 1. **Add a number** to the list. This function is called `add_number` and takes an integer as input. 2. **Remove a number** from a specified position in the list if the position is valid. This function is called `remove_number` and takes an integer position as input. 3. **Query the sum** of numbers between two specified indices (inclusive). This function is called `range_sum` and takes two integers representing the start and end indices as input. # Input The following operations should be supported: - `"add_number x"`: Add the number `x` to the list. `x` is an integer (1 ≤ x ≤ 10^6). - `"remove_number p"`: Remove the number at position `p` from the list (0-based index). `p` is an integer (0 ≤ p < current size of the list). - `"range_sum a b"`: Return the sum of numbers between indices `a` and `b` (0 ≤ a ≤ b < current size of the list). Initially, the list is empty. # Output For each `"range_sum a b"` operation, return the sum of the elements from index `a` to `b` in the list. # Constraints - The total number of operations (queries + additions + removals) will not exceed 5000. - List elements and results of range sums will fit within the bounds of a standard integer. # Example ```plaintext Input 7 add_number 5 add_number 3 add_number 8 range_sum 0 2 remove_number 1 range_sum 0 1 add_number 1 range_sum 1 2 Output 16 13 9 ``` In this example: - First, we add numbers 5, 3, and 8 to the list. - The range sum query from index 0 to 2 (inclusive) returns 16 (5+3+8). - Next, we remove the number at position 1, resulting in the list [5, 8]. - Querying the sum from index 0 to 1 now returns 13 (5+8). - Adding the number 1 results in the list [5, 8, 1]. - Finally, querying the sum from index 1 to 2 returns 9 (8+1).
answer:class DynamicRangeSum: def __init__(self): self.numbers = [] def add_number(self, x): self.numbers.append(x) def remove_number(self, p): if 0 <= p < len(self.numbers): self.numbers.pop(p) def range_sum(self, a, b): if 0 <= a <= b < len(self.numbers): return sum(self.numbers[a:b+1]) return 0