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question:Given a list of integers `nums`, find the maximum product of any two distinct elements in the list. Return the maximum product. For example, given `nums = [5, 3, -1, 9, -7]`, the maximum product would be `5 * 9 = 45`.

answer:def max_product(nums): Returns the maximum product of any two distinct elements in the list. # Sort the list nums.sort() # The maximum product could be from the two highest values or two lowest values (in case they are negative) return max(nums[-1] * nums[-2], nums[0] * nums[1])

question:Given a list of integers `nums`, consider a list of all possible subarrays. Return the length of the shortest subarray whose sum is equal to or greater than a given integer `target`. If no such subarray exists, return 0.

answer:def min_subarray_len(target, nums): Returns the length of the shortest subarray whose sum is equal to or greater than target. If no such subarray exists, return 0. n = len(nums) min_length = float('inf') current_sum = 0 start = 0 for end in range(n): current_sum += nums[end] while current_sum >= target: min_length = min(min_length, end - start + 1) current_sum -= nums[start] start += 1 return 0 if min_length == float('inf') else min_length

question:Given an array of integers `arr`, you are to form a sequence by starting from the first element and at each step moving to the next different element (i.e., an element that hasn't been visited yet in the current sequence). Your task is to find the length of the longest subsequence that can be formed following this rule. Return _the length of the longest subsequence_ of `arr` where each element in the subsequence is distinct and followed by the next different element in the original array.

answer:def longest_distinct_subsequence(arr): Returns the length of the longest subsequence of distinct elements by moving to the next different element in the array. Parameters: arr (list): List of integers. Returns: int: Length of the longest subsequence with distinct elements. if not arr: return 0 seen = set() subsequence_length = 0 for num in arr: if num not in seen: seen.add(num) subsequence_length += 1 return subsequence_length

question:A tropical island is represented by a grid of size `m x n` where each cell contains a certain number of coconuts. You are positioned at the top-left cell of the grid and want to collect coconuts while moving to the bottom-right cell. You can only move either down or right at any point in time. Write an algorithm to find the maximum number of coconuts you can collect on your way. The grid is given as a 2D array `coconuts` where `coconuts[i][j]` represents the number of coconuts in the cell `(i, j)`. Return _the maximum number of coconuts you can collect_.

answer:def max_coconuts(coconuts): Find the maximum number of coconuts that can be collected while moving from the top-left to the bottom-right of the grid. if not coconuts or not coconuts[0]: return 0 m, n = len(coconuts), len(coconuts[0]) dp = [[0] * n for _ in range(m)] dp[0][0] = coconuts[0][0] # Initialize first row for j in range(1, n): dp[0][j] = dp[0][j-1] + coconuts[0][j] # Initialize first column for i in range(1, m): dp[i][0] = dp[i-1][0] + coconuts[i][0] # Fill the rest of dp table for i in range(1, m): for j in range(1, n): dp[i][j] = max(dp[i-1][j], dp[i][j-1]) + coconuts[i][j] return dp[m-1][n-1]