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question:I have a equation in the form y = f(x) = (e^(x - 1) - 1) / (e^(x - 1) + 1). I need to plot this function over a range of x values. I will use Python with matplotlib and numpy to do this. I can generate x values using numpy's linspace function, which gives me 50 numbers over a specified range. I will use these x values to calculate the corresponding y values using my function. Here's a sample code to generate the plot ```python import numpy as np import matplotlib.pyplot as plt def f(x): return (np.exp(x - 1) - 1) / (np.exp(x - 1) + 1) x = np.linspace(-10, 10, 50) y = f(x) plt.plot(x, y) plt.show() ``` This will generate the plot for the given function. However, I want to visually inspect the function behavior over different ranges. I want to plot the function over the following ranges: - (-10, 2) - (-5, 5) - (-1, 3) - (0, 4) - (-2, 2) - (-10, 10) I can repeat the code for each range, but I want a more efficient way to do this. How can I modify the existing code to generate plots for all the given ranges without repeating the code for each range?
answer:import numpy as np import matplotlib.pyplot as plt def f(x): return (np.exp(x - 1) - 1) / (np.exp(x - 1) + 1) def plot_function(f, ranges): for r in ranges: x = np.linspace(r[0], r[1], 50) y = f(x) plt.plot(x, y, label=f'x in {r}') plt.legend() plt.show() ranges = [(-10, 2), (-5, 5), (-1, 3), (0, 4), (-2, 2), (-10, 10)] plot_function(f, ranges)
question:# Solution Explanation Here's a concise explanation of the code: * The solution utilizes a priority queue data structure. * We initialize the priority queue with the initial temperatures and their indices. * Then we start a while loop that continues until the priority queue is empty. * Inside the loop, we pop the largest temperature (the top of the priority queue) and its index. * We then check all previous temperatures to see if they are lower than the current temperature. * If a previous temperature is lower, we calculate the number of days until it warms up and update the result list. ```python import heapq from typing import List def dailyTemperatures(temperatures: List[int]) -> List[int]: This function takes a list of temperatures as input and returns a list of the number of days until it warms up. :param temperatures: A list of temperatures :return: A list of the number of days until it warms up # Initialize the result list with zeros result = [0] * len(temperatures) # Initialize the priority queue with the initial temperatures and their indices pq = [] for i, temp in enumerate(temperatures): # Push the temperature and its index into the priority queue # We use a max heap, so we push the negative of the temperature # The index is also pushed to keep track of the position in the result list heapq.heappush(pq, (-temp, i)) # Start a while loop that continues until the priority queue is empty while pq: # Pop the largest temperature (the top of the priority queue) and its index temp, i = heapq.heappop(pq) # Check all previous temperatures to see if they are lower than the current temperature for j in range(i - 1, -1, -1): # If a previous temperature is lower, calculate the number of days until it warms up and update the result list if temperatures[j] < -temp: result[j] = i - j # If a previous temperature is not lower, we can break the loop because the list is sorted else: break return result ``` # Example Use Cases Here are some example use cases for the `dailyTemperatures` function: ```python # Example 1: # Input: temperatures = [73,74,75,71,69,72,76,73] # Output: [1, 1, 4, 2, 1, 1, 0, 0] print(dailyTemperatures([73,74,75,71,69,72,76,73])) # Example 2: # Input: temperatures = [10,20,30,40,50,60] # Output: [1, 1, 1, 1, 1, 0] print(dailyTemperatures([10,20,30,40,50,60])) # Example 3: # Input: temperatures = [60,50,40,30,20,10] # Output: [0, 0, 0, 0, 0, 0] print(dailyTemperatures([60,50,40,30,20,10])) ``` What would be a more efficient solution to find the number of days until it warms up?
answer:from typing import List def dailyTemperatures(temperatures: List[int]) -> List[int]: This function takes a list of daily temperatures and returns a list of the number of days until a warmer temperature. :param temperatures: A list of integers representing the daily temperatures. :return: A list of integers representing the number of days until a warmer temperature. result = [0] * len(temperatures) stack = [] for current_day, current_temp in enumerate(temperatures): while stack and temperatures[stack[-1]] < current_temp: prev_day = stack.pop() result[prev_day] = current_day - prev_day stack.append(current_day) return result
question:Here is the problem: Find the length of the longest common prefix of the given array of strings `strs`. Example 1: Input: strs = ["flower","flow","flight"] Output: "fl" Example 2: Input: strs = ["dog","racecar","car"] Output: "" Example 3: Input: strs = ["ab", "abc", "abcd"] Output: "ab" Constraints: * 1 <= strs.length <= 200 * 0 <= strs[i].length <= 100 * strs[i] consists of lowercase English letters. Here is my solution: ```python def longest_common_prefix(strs): if not strs: return "" shortest_str = min(strs, key=len) for i, char in enumerate(shortest_str): for string in strs: if string[i] != char: return shortest_str[:i] return shortest_str
answer:def longest_common_prefix(strs): Finds the longest common prefix in an array of strings. Parameters: strs (List[str]): A list of strings. Returns: str: The longest common prefix. if not strs: return "" shortest_str = min(strs, key=len) for i, char in enumerate(shortest_str): for string in strs: if string[i] != char: return shortest_str[:i] return shortest_str
question:You've been asked to create a function `prepare_for_review` which takes in a list of employee objects. Each employee object has the following attributes: `name`, `email`, `performance_rating` (a float representing the performance rating of the employee on a scale of 1 to 5), and `is_manager` (a boolean indicating whether the employee is a manager). The function should return the list of employees sorted by `performance_rating` in descending order. If two employees have the same `performance_rating`, they should be sorted by `name` in ascending order.
answer:def prepare_for_review(employees): Returns the list of employees sorted by performance rating in descending order. If two employees have the same performance rating, they are sorted by name in ascending order. return sorted(employees, key=lambda x: (-x['performance_rating'], x['name']))