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question:def library_management(events): Determine the final status of each book in the library based on a series of check-in and check-out events. Args: events (List[str]): A list of strings representing the events in chronological order. Each event is either "CheckIn <book_id>" or "CheckOut <book_id>". Returns: List[Tuple[str, str]]: A list of tuples where each tuple contains a book ID and its final status, either "Available" or "Checked Out". The books should be sorted in lexicographical order by ID. >>> library_management(["CheckIn book1", "CheckOut book1", "CheckIn book2", "CheckOut book2", "CheckIn book3", "CheckOut book3"]) [('book1', 'Checked Out'), ('book2', 'Checked Out'), ('book3', 'Checked Out')] >>> library_management(["CheckIn bookA", "CheckOut bookA", "CheckIn bookB", "CheckIn bookC", "CheckOut bookB"]) [('bookA', 'Checked Out'), ('bookB', 'Checked Out'), ('bookC', 'Available')] >>> library_management(["CheckIn book1", "CheckIn book2", "CheckIn book1"]) [('book1', 'Available'), ('book2', 'Available')] >>> library_management(["CheckIn xyz", "CheckOut xyz", "CheckIn abc", "CheckOut abc", "CheckIn lmn"]) [('abc', 'Checked Out'), ('lmn', 'Available'), ('xyz', 'Checked Out')] >>> library_management(["CheckIn bookA", "CheckOut bookA", "CheckIn bookA"]) [('bookA', 'Available')]
answer:def library_management(events): book_status = {} for event in events: action, book_id = event.split() if action == "CheckIn": book_status[book_id] = "Available" elif action == "CheckOut": book_status[book_id] = "Checked Out" sorted_books = sorted(book_status.items()) return sorted_books # Function to transform input and output def process_library_events(t, event_list): events = [input().strip() for _ in range(t)] final_status = library_management(events) for book_id, status in final_status: print(f"{book_id} {status}")
question:from typing import List, Dict def find_longest_activity(n: int, activity_log: List[str]) -> Dict[str, str]: Determines the most time-consuming activity for each day based on the input data. Parameters: n (int): The number of activities logged. activity_log (List[str]): List of strings representing activities along with corresponding time. Returns: Dict[str, str]: A dictionary where keys are the days and values are the most time-consuming activities. >>> find_longest_activity(5, ["2023-10-01 Reading - 02:30:00", "2023-10-01 Coding - 01:45:00", "2023-10-02 Meeting - 02:00:00", "2023-10-02 Emails - 01:15:00", "2023-10-01 Jogging - 00:45:00"]) {'2023-10-01': 'Reading', '2023-10-02': 'Meeting'} >>> find_longest_activity(3, ["2023-09-15 Exam - 03:00:00", "2023-09-15 Preparation - 03:00:00", "2023-09-16 Homework - 02:30:00"]) {'2023-09-15': 'Exam', '2023-09-16': 'Homework'}
answer:from datetime import timedelta def find_longest_activity(n, activity_log): Determines the most time-consuming activity for each day based on the input data. Parameters: n (int): The number of activities logged. activity_log (List[str]): List of strings representing activities along with corresponding time. Returns: dict: A dictionary where keys are the days and values are the most time-consuming activities. activities = {} for entry in activity_log: day_activity, time = entry.rsplit(' - ', 1) day, activity = day_activity.split(' ', 1) hours, minutes, seconds = map(int, time.split(':')) duration = timedelta(hours=hours, minutes=minutes, seconds=seconds) if day not in activities or duration > activities[day][1]: activities[day] = (activity, duration) result = {day: activities[day][0] for day in sorted(activities)} return result
question:def rank_players(test_cases): Ranks the players based on their total scores in descending order. If two players have the same score, they are ranked alphabetically by their names. :param test_cases: List of test cases where each case is a list of tuples containing player's name and score. :return: List of lists where each list contains ranked player names for the corresponding test case. pass # Unit tests def test_rank_single_test_case(): test_cases = [ [("Alice", 100), ("Bob", 200), ("Charlie", 150)] ] expected_output = [ ["Bob", "Charlie", "Alice"] ] assert rank_players(test_cases) == expected_output def test_rank_multiple_test_cases(): test_cases = [ [("Alice", 100), ("Bob", 200), ("Charlie", 150)], [("Dave", 300), ("Eve", 300), ("Frank", 100), ("Grace", 200)] ] expected_output = [ ["Bob", "Charlie", "Alice"], ["Dave", "Eve", "Grace", "Frank"] ] assert rank_players(test_cases) == expected_output def test_rank_same_score_alphabetical_order(): test_cases = [ [("Alice", 100), ("Bob", 100), ("Charlie", 100)] ] expected_output = [ ["Alice", "Bob", "Charlie"] ] assert rank_players(test_cases) == expected_output def test_rank_single_player(): test_cases = [ [("Alice", 100)] ] expected_output = [ ["Alice"] ] assert rank_players(test_cases) == expected_output def test_rank_no_players(): test_cases = [ [] ] expected_output = [ [] ] assert rank_players(test_cases) == expected_output
answer:def rank_players(test_cases): Ranks the players based on their total scores in descending order. If two players have the same score, they are ranked alphabetically by their names. :param test_cases: List of test cases where each case is a list of tuples containing player's name and score. :return: List of lists where each list contains ranked player names for the corresponding test case. result = [] for case in test_cases: players = [(name, score) for name, score in case] players.sort(key=lambda x: (-x[1], x[0])) # sort by score desc and name asc ranked_names = [name for name, score in players] result.append(ranked_names) return result
question:def max_money(coins: List[int]) -> int: Determine the maximum amount of money Alice can collect if both players play optimally. >>> max_money([1, 2, 9, 4]) 10 >>> max_money([4, 4, 4]) 8
answer:def max_money(coins): n = len(coins) dp = [[0] * n for _ in range(n)] for length in range(1, n + 1): for i in range(n - length + 1): j = i + length - 1 if i == j: dp[i][j] = coins[i] else: pick_i = coins[i] + min(dp[i + 2][j] if i + 2 <= j else 0, dp[i + 1][j - 1] if i + 1 <= j - 1 else 0) pick_j = coins[j] + min(dp[i][j - 2] if i <= j - 2 else 0, dp[i + 1][j - 1] if i + 1 <= j - 1 else 0) dp[i][j] = max(pick_i, pick_j) return dp[0][n - 1] # Example usage: # coins = [1, 2, 9, 4] # print(max_money(coins)) # Output should be 10