Appearance
question:Given an array of integers nums, return the length of the longest strictly decreasing subsequence (LDS) in nums. A strictly decreasing subsequence is defined as a subsequence where for all i < j, nums[i] > nums[j]. Constraints * 1 ≤ nums.length ≤ 100000 * -109 ≤ nums[i] ≤ 109 Input First line: An integer n denoting the number of elements in the array. Next n lines: n integers representing the elements of the array. Output An integer representing the length of the longest strictly decreasing subsequence. Examples Input 6 9 4 3 8 6 7 Output 3 Input 4 10 20 30 0 Output 2
answer:def length_of_lds(nums): Returns the length of the longest strictly decreasing subsequence (LDS) in nums. if not nums: return 0 n = len(nums) dp = [1] * n # Initialize dp array where dp[i] is the length of LDS ending at index i for i in range(1, n): for j in range(i): if nums[j] > nums[i]: dp[i] = max(dp[i], dp[j] + 1) return max(dp) # Function to process input and call the length_of_lds function def process_input_and_find_lds(): import sys input = sys.stdin.read data = input().split() n = int(data[0]) nums = [int(data[i + 1]) for i in range(n)] return length_of_lds(nums)
question:Given an integer array of size N, find two indices i and j such that the absolute difference between nums[i] and nums[j] is equal to a given integer k (i.e., |nums[i] - nums[j]| = k). You may assume that each input would have exactly one solution, and you may not use the same element twice. INPUT::: The first line contains an integer T, the number of test cases. Each test case contains an integer N, the size of the array, followed by N space-separated integers representing the array elements. The last element in the line is the integer k. OUTPUT::: For each test case, print two space-separated integers i and j (0-indexed) representing the indices such that |nums[i] - nums[j]| = k. Constraints::: 1≤T≤10, 2≤N≤1000, -10^6≤nums[i]≤10^6, 1≤k≤10^6. Note::: Return the indices (i, j) in sorted order if multiple solutions are possible. SAMPLE INPUT 2 5 1 7 5 9 2 4 4 10 5 7 1 2 SAMPLE OUTPUT 0 2 1 3
answer:def find_indices_for_difference(test_cases): Finds indices i and j such that |nums[i] - nums[j]| = k. Parameters: test_cases (list of tuples): Each tuple contains (N, nums, k) Returns: list of tuples: Each tuple contains indices (i, j) results = [] for case in test_cases: N, nums, k = case index_map = {} for i in range(N): complement1 = nums[i] + k complement2 = nums[i] - k if complement1 in index_map: results.append((index_map[complement1], i)) break if complement2 in index_map: results.append((index_map[complement2], i)) break index_map[nums[i]] = i return results
question:**Context:** Tina loves baking cakes and she is experimenting with various recipes. For each recipe, Tina needs exact measurements of ingredients. She realized that her baking process could be more efficient if she writes a program to calculate the exact measurements for a given number of cakes. # Task: You need to write a program that helps Tina calculate the required amount of each ingredient based on the recipe for a single cake and the number of cakes she wants to bake. # Input: - The first line contains an integer `m` (1 ≤ m ≤ 100) — the number of ingredients in the recipe. - The second line contains `m` integers `u1, u2, ..., um` (1 ≤ ui ≤ 1000) — the units of each ingredient required for one cake. - The third line contains an integer `k` (1 ≤ k ≤ 1000) — the number of cakes Tina wants to bake. # Output: Print a single line containing `m` integers — the units of each ingredient required for `k` cakes. # Example: Input: ``` 3 100 200 150 5 ``` Output: ``` 500 1000 750 ``` # Explanation: In the example given: - Tina requires 100 units of ingredient 1, 200 units of ingredient 2, and 150 units of ingredient 3 to bake one cake. - For 5 cakes, she needs 5 * 100 = 500 units of ingredient 1, 5 * 200 = 1000 units of ingredient 2, and 5 * 150 = 750 units of ingredient 3. - Therefore, the output is "500 1000 750".
answer:def calculate_ingredients(m, ingredient_units, k): Calculates the required amount of each ingredient for making k cakes. Parameters: m (int): Number of ingredients. ingredient_units (list[int]): Units of each ingredient required for one cake. k (int): Number of cakes to bake. Returns: list[int]: Units of each ingredient required for k cakes. return [units * k for units in ingredient_units]
question:Given a list of integers, find the longest sublist such that the sum of its elements is even. Input The first line contains an integer n (1 ≤ n ≤ 100) — the number of elements in the list. The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100) — the elements of the list. Output You should output the length of the longest sublist such that the sum of its elements is even. If all elements of the list are odd and there is no sublist with an even sum, print "0" (without quotes). Examples Input 5 1 2 3 4 5 Output 4 Input 3 1 1 1 Output 2
answer:def longest_even_sum_sublist(n, arr): Returns the length of the longest sublist with even sum. If there is no such sublist, it returns 0. # Total sum of the array total_sum = sum(arr) # If the total sum is even, the whole list is the longest even-sum sublist if total_sum % 2 == 0: return n # Check the first and last odd number to minimize the removal to make sum even first_odd_index = -1 last_odd_index = -1 for i in range(n): if arr[i] % 2 != 0: if first_odd_index == -1: first_odd_index = i last_odd_index = i if first_odd_index == -1: # No odd numbers were found, meaning all are even return n # If we remove first or last odd number and the rest sum is even max_length_after_removal = max(n - first_odd_index - 1, last_odd_index) return max_length_after_removal