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question:There are M robots and N commands in a 2D grid. Each robot starts at a given position and each command is a move that one robot can perform. The grid has rows from 1 to R and columns from 1 to C. The commands are given as follows: * Each command applies to a specific robot and moves it one step in one of the four cardinal directions: "U" (up), "D" (down), "L" (left), and "R" (right). Write a program to determine the final positions of all the robots after performing all the commands. Constraints * 1 ≤ M ≤ 100 * 1 ≤ N ≤ 1000 * 1 ≤ R, C ≤ 10^6 * 1 ≤ robot_id ≤ M * The starting coordinates and the dimensions of the grid are integers. Input Input is given from Standard Input in the following format: R C M N x1 y1 x2 y2 ... xM yM robot_id1 move1 robot_id2 move2 ... robot_idN moveN Output Print M lines. Each line should contain two integers representing the final coordinates (xi yi) of the i-th robot. Examples Input 5 5 3 4 1 1 2 2 3 3 1 R 2 U 1 R 3 D Output 3 1 2 3 3 2 Input 4 4 2 3 4 4 1 1 1 L 2 D 1 U Output 3 4 1 2
answer:def move_robots(grid_size, robot_start_positions, commands): R, C = grid_size M = len(robot_start_positions) robots = robot_start_positions[:] for command in commands: robot_id, move = command x, y = robots[robot_id - 1] if move == 'U' and y < R: y += 1 elif move == 'D' and y > 1: y -= 1 elif move == 'L' and x > 1: x -= 1 elif move == 'R' and x < C: x += 1 robots[robot_id - 1] = (x, y) return robots def prepare_input(input_data): lines = input_data.strip().split('n') R, C, M, N = map(int, lines[0].split()) robot_start_positions = [] for i in range(1, M + 1): x, y = map(int, lines[i].split()) robot_start_positions.append((x, y)) commands = [] for i in range(M + 1, M + 1 + N): parts = lines[i].split() robot_id = int(parts[0]) move = parts[1] commands.append((robot_id, move)) return (R, C), robot_start_positions, commands def main(input_data): grid_size, robot_start_positions, commands = prepare_input(input_data) final_positions = move_robots(grid_size, robot_start_positions, commands) for pos in final_positions: print(pos[0], pos[1]) # Sample input and function usage: input_data = 5 5 3 4 1 1 2 2 3 3 1 R 2 U 1 R 3 D main(input_data)
question:Sara loves reading and writing about books. She wants to create a system to manage books in her library. Each book can be identified by its unique ISBN number and has a title, an author, and a published year. Sara wants to efficiently add books to her collection, look up books by their ISBN number, and list all books by a specific author in chronological order. Write a program for Sara's library management system with the following functionalities: 1. Add a new book to the collection. 2. Look up a book by its ISBN and display its details. 3. List all books by a given author, sorted by their published year in ascending order. Input The first line contains an integer `q` (1 ≤ q ≤ 10^5), the number of operations. Each of the next `q` lines describes an operation in one of the following formats: - `1 ISBN Title Author Year` - Add a new book with the given ISBN (a string), Title (a string with spaces), Author (a string), and Year (an integer, 1000 ≤ Year ≤ 9999). - `2 ISBN` - Look up the book with the given ISBN and print its details. - `3 Author` - List all books by the given author, sorted by their published year in ascending order. Output For each operation of type `2`, print the details of the book in the format `Title Author Year`. If the book is not found, print `Book not found`. For each operation of type `3`, print the details of each book by the given author sorted by published year in ascending order in the format `Title ISBN Year`, one book per line. If no books are found by the given author, print `No books found by Author`. Examples Input: ``` 6 1 978-3-16-148410-0 The_Catcher_in_the_Rye J.D_Salinger 1951 1 978-0-14-044913-6 Anna_Karenina Leo_Tolstoy 1878 2 978-3-16-148410-0 3 Leo_Tolstoy 3 J.D_Salinger 2 978-1-56619-909-4 ``` Output: ``` The_Catcher_in_the_Rye J.D_Salinger 1951 Anna_Karenina 978-0-14-044913-6 1878 The_Catcher_in_the_Rye J.D_Salinger 1951 Book not found ``` Note - In the first `2` operation, the system displays the details of the book with ISBN `978-3-16-148410-0`. - In the first `3` operation, the system lists the book by Leo Tolstoy. - In the second `3` operation, the system lists the book by J.D. Salinger. - In the second `2` operation, the system returns `Book not found` since there's no such ISBN in the collection. Make sure to optimize the solution for efficiency given the constraints.
answer:class LibrarySystem: def __init__(self): self.books_by_isbn = {} self.books_by_author = {} def add_book(self, isbn, title, author, year): self.books_by_isbn[isbn] = (title, author, year) if author not in self.books_by_author: self.books_by_author[author] = [] self.books_by_author[author].append((year, title, isbn)) self.books_by_author[author].sort() def lookup_by_isbn(self, isbn): if isbn in self.books_by_isbn: title, author, year = self.books_by_isbn[isbn] return f"{title} {author} {year}" else: return "Book not found" def list_books_by_author(self, author): if author in self.books_by_author: return [f"{title} {isbn} {year}" for year, title, isbn in self.books_by_author[author]] else: return f"No books found by {author}" # Simulation of operations on the library def execute_operations(operations): library = LibrarySystem() results = [] for operation in operations: op = operation.split() op_code = int(op[0]) if op_code == 1: # Add a new book isbn = op[1] title = " ".join(op[2:-2]) author = op[-2] year = int(op[-1]) library.add_book(isbn, title, author, year) elif op_code == 2: # Look up a book by ISBN isbn = op[1] results.append(library.lookup_by_isbn(isbn)) elif op_code == 3: # List all books by author author = op[1] results.append("n".join(library.list_books_by_author(author))) return results
question:Iahub loves cooking meals with certain ingredients. He wants to create a meal that contains exactly m different ingredients out of the possible n ingredients he has. He wants to know in how many ways he can choose these m ingredients from n ingredients, considering the order in which ingredients are chosen does not matter. Input The first line contains two integers n and m (1 ≤ m ≤ n ≤ 1000). Output Output a single integer, the number of ways to choose m ingredients from n ingredients. Examples Input 5 3 Output 10 Input 6 2 Output 15
answer:from math import comb def choose_ingredients(n, m): Returns the number of ways to choose m ingredients from n ingredients. return comb(n, m)
question:Polycarp recently discovered that some websites handle URLs in a way that they redirect to canonical URLs. Specifically, some websites leverage URL shortening services, others might consider URLs with www and without www as the same, and some even ignore or change parameters in the URL query string except specific parameters. In this problem, every URL is defined by: - `protocol` which is either `http` or `https`. - `www` which can either be present or absent. - `domain` which is a set of alphanumeric characters and possibly hyphens. - `path` which is a set of alphanumeric characters and possibly hyphens and slashes. - `query` which contains key-value parameters. Each key and value is alphanumeric, and multiple parameters are connected by '&' sign. To simplify: 1. URLs with `http` and `https` are considered distinct. 2. URLs with or without `www` are regarded as equivalent. 3. If `query` parameters are present, their order does not matter, but every specific key-value pair matters. For example, the URLs "http://example.com/path?b=2&a=1" and "http://www.example.com/path?a=1&b=2" correspond to the same URL. But "https://example.com/path?a=1&b=2" is a different URL than the former. Polycarp has to group URLs according to these rules and merge equivalent URLs. Input: - The first line contains an integer `n` (1 ≤ n ≤ 20000) — the number of URLs in Polycarp's list. - The following `n` lines contain URLs, one per line. It is guaranteed that all of them are correctly formatted and distinct. Output: - Print the number of groups `k` and then in `k` lines print the description of every group. - In the i-th line, print the number of URLs in the group and all URLs that belong to the i-th group, separated by a space. You can print the groups and URLs in any order. - Print the URLs exactly as they were given in the input. Each URL should belong to exactly one group. Examples: Input: 6 http://example.com/path?a=1&b=2 https://example.com/path?a=1&b=2 http://www.example.com/path?b=2&a=1 http://example.com/otherpath?p=5&q=4 http://www.example.com/path?a=2&b=1 http://example.com/about?x=3 Output: 4 2 http://example.com/path?a=1&b=2 http://www.example.com/path?b=2&a=1 1 https://example.com/path?a=1&b=2 1 http://example.com/otherpath?p=5&q=4 1 http://example.com/about?x=3
answer:from urllib.parse import urlparse, parse_qsl def canonical_url(url): Converts a URL into its canonical form by: - Removing 'www.' if it exists - Sorting the query parameters parsed_url = urlparse(url) # Remove 'www.' if it exists netloc = parsed_url.netloc.replace('www.', '', 1) # Parse and sort the query parameters query_params = parse_qsl(parsed_url.query) sorted_query = sorted(query_params) query_string = '&'.join([f'{key}={value}' for key, value in sorted_query]) # Return the canonical URL canonical = f"{parsed_url.scheme}://{netloc}{parsed_url.path}" if query_string: canonical += f"?{query_string}" return canonical def group_urls(urls): Groups the URLs into their respective canonical forms. from collections import defaultdict url_groups = defaultdict(list) url_to_canonical = {} for url in urls: canon = canonical_url(url) url_groups[canon].append(url) url_to_canonical[url] = canon grouped_urls = list(url_groups.values()) return grouped_urls def merge_urls(n, url_list): Given the number of URLs and the list of URLs, returns the grouped URLs. grouped_urls = group_urls(url_list) return grouped_urls