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question:In this exercise, you will work with Python's string methods and list operations to accomplish text-related tasks. This problem will test your ability to manipulate strings and lists and apply basic programming techniques. You are required to create a function named `string_manipulations` which performs the following tasks: 1. Given a string sentence, create a list of its words. 2. Compute the frequency of each word in the list. 3. Find the word that has the maximum frequency. If there is a tie, choose the word that appears first in the list. 4. Return the list of words, the frequency dictionary, and the most frequent word. The function should return a tuple with three elements in the following order: - The list of words in the sentence. - A dictionary containing the frequency of each word. - The word with the highest frequency. # Function Signature The signature of the function is: ```python def string_manipulations(sentence: str) -> tuple: pass ``` # Example ```python sentence = "the quick brown fox jumps over the lazy dog the quick dog" result = string_manipulations(sentence) print(result) ``` Output: ``` (['the', 'quick', 'brown', 'fox', 'jumps', 'over', 'the', 'lazy', 'dog', 'the', 'quick', 'dog'], {'the': 3, 'quick': 2, 'brown': 1, 'fox': 1, 'jumps': 1, 'over': 1, 'lazy': 1, 'dog': 2}, 'the') ``` # Constraints - Assume the input string is non-empty and contains only alphabetical characters and spaces. - The words are separated by single spaces. - The function should handle both uppercase and lowercase letters by converting the entire sentence to lowercase before processing. Use Python's built-in string methods and dictionary operations to solve this problem. Ensure that the string is correctly split into words, and the frequency calculation is accurate.
answer:def string_manipulations(sentence: str) -> tuple: # Convert the sentence to lowercase sentence = sentence.lower() # Create a list of words words = sentence.split() # Compute the frequency of each word frequency = {} for word in words: if word in frequency: frequency[word] += 1 else: frequency[word] = 1 # Find the word with the maximum frequency max_frequency = 0 max_word = None for word in words: if frequency[word] > max_frequency: max_frequency = frequency[word] max_word = word return (words, frequency, max_word)
question:You need to implement a function `group_students` that groups students into study teams based on their skill levels and preferences. Each student has a unique identifier, a skill level (an integer), and a list of preferred teammates' identifiers. The goal is to maximize the number of groups formed of exactly three students where each student in the group prefers being with the other two members, and their skill levels are within a given range of each other. The function `group_students` should: 1. Iterate over the list of students, their skill levels, and preferences. 2. Form teams of exactly three students where: - Each student in the team prefers the other two students. - The difference in skill levels between the highest and lowest in the team does not exceed the given `max_skill_diff`. 3. Return the number of such groups formed. **Function Signature:** ```python def group_students(students: list[dict], max_skill_diff: int) -> int: pass ``` **Parameters:** - `students` (list of dicts): A list of dictionaries, each representing a student with keys: - `'id'` (int): The student's unique identifier. - `'skill_level'` (int): The student's skill level. - `'preferences'` (list of int): List of other student identifiers this student prefers to work with. - `max_skill_diff` (int): The maximum allowed difference between the highest and lowest skill levels in a team. **Returns:** - `int`: The number of valid teams (groups of exactly three students) formed. **Example Usage:** ```python students = [ {'id': 1, 'skill_level': 5, 'preferences': [2, 3]}, {'id': 2, 'skill_level': 6, 'preferences': [1, 3]}, {'id': 3, 'skill_level': 7, 'preferences': [1, 2]}, {'id': 4, 'skill_level': 4, 'preferences': [5, 6]}, {'id': 5, 'skill_level': 5, 'preferences': [4, 6]}, {'id': 6, 'skill_level': 6, 'preferences': [4, 5]} ] group_count = group_students(students=students, max_skill_diff=2) print(group_count) # Expected output: 2 (one group being [1, 2, 3] and another being [4, 5, 6]) ``` **Important Notes:** - A student can be part of at most one team. - Consider the order of students in the `preferences` list while forming the groups. - Ensure the function efficiently handles the grouping to avoid excessive computation time with large input sizes.
answer:from itertools import combinations def group_students(students, max_skill_diff): Groups students into teams of exactly three where each student in the group prefers the other two members and their skill levels are within a given range. Args: - students (list of dict): List of dictionaries each representing a student. - max_skill_diff (int): Maximum allowed difference between highest and lowest skill levels in a team. Returns: - int: Number of valid teams formed. # Helper function to check if three students can form a group def can_form_group(student1, student2, student3): ids = [student1['id'], student2['id'], student3['id']] skill_levels = [student1['skill_level'], student2['skill_level'], student3['skill_level']] preferences = [student1['preferences'], student2['preferences'], student3['preferences']] if all(x in preferences[0] for x in ids if x != student1['id']) and all(x in preferences[1] for x in ids if x != student2['id']) and all(x in preferences[2] for x in ids if x != student3['id']): if max(skill_levels) - min(skill_levels) <= max_skill_diff: return True return False valid_groups = [] student_ids_in_group = set() for combo in combinations(students, 3): if can_form_group(*combo): # Make sure no student is already in a group if not any(student['id'] in student_ids_in_group for student in combo): valid_groups.append(combo) student_ids_in_group.update(student['id'] for student in combo) return len(valid_groups)
question:You've been hired to work on a project that involves processing text data from a list of phrases. Each phrase contains words that might be repeated. Your task is to write a function `filter_unique_words(phrases)` that filters out repeated words within each phrase and retains only the unique ones in their original order. Here's the requirement for the function: 1. Traverse through each phrase in the `phrases` list. 2. For each phrase, extract each word and keep track of words that have already appeared within that phrase. 3. If a word appears more than once in the same phrase, discard its subsequent occurrences. 4. Create a new list of phrases containing only the unique words for each original phrase, maintaining their order of first appearance. 5. Return the new list of phrases. # Function Signature: ```python def filter_unique_words(phrases): pass ``` # Constraints: - The input `phrases` is a list of strings, where each string is a phrase composed of words separated by spaces. - Words are case-sensitive, e.g., 'Hello' and 'hello' are considered different words. - The maximum number of phrases is 100. - Each phrase can contain up to 100 words. # Example Usage: ```python phrases = [ "this is a test test", "hello world world hello", "python is great python programming" ] print(filter_unique_words(phrases)) # Output: [ # "this is a test", # "hello world", # "python is great programming" # ] ```
answer:def filter_unique_words(phrases): Filters out repeated words within each phrase and retains only the unique ones in their original order. new_phrases = [] for phrase in phrases: words = phrase.split() seen = set() unique_words = [] for word in words: if word not in seen: seen.add(word) unique_words.append(word) new_phrases.append(" ".join(unique_words)) return new_phrases
question:Your task is to create a function that takes a list of integers and returns a tuple containing two lists. The first list should contain all the even integers from the input list, and the second list should contain all the odd integers. Ensure that the integers in each list maintain their original order as in the input list. The function should output: tuple: A tuple containing two lists (even_list, odd_list). You should write self-contained code starting with: ``` def task_func(int_list): ```
answer:def task_func(int_list): Takes a list of integers and returns a tuple containing two lists: one with even integers and another with odd integers. Parameters: int_list (list): A list of integers. Returns: tuple: A tuple containing two lists (even_list, odd_list). even_list = [num for num in int_list if num % 2 == 0] odd_list = [num for num in int_list if num % 2 != 0] return (even_list, odd_list)