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question:You are given two strings s and t. Your task is to determine if you can make the string t a subsequence of the string s by deleting at most one character from s. If it is impossible, return "NO"; otherwise, return "YES". The first line contains one integer n (1 le n le 100) — the number of test cases. Each of the next n lines contains two strings s and t (1 le |s|, |t| le 100). For each test case, print "YES" if you can make t a subsequence of s by deleting at most one character from s. Otherwise, print "NO". # Example Input: 4 abcde ace hello helo codeforces codefrces coding cnoding Output: YES YES YES NO Explanation: In the first test case, t is already a subsequence of s. In the second test case, deleting character 'l' from "hello" results in "helo". In the third test case, deleting character 'o' from "codeforces" results in "codefrces". In the fourth test case, deleting one character won't make "cnoding" a subsequence of "coding".

answer:def can_form_subsequence(s, t): def is_subsequence(s, t): it = iter(s) return all(c in it for c in t) if is_subsequence(s, t): return "YES" for i in range(len(s)): modified_s = s[:i] + s[i+1:] if is_subsequence(modified_s, t): return "YES" return "NO" def solve(test_cases): results = [] for s, t in test_cases: results.append(can_form_subsequence(s, t)) return results

question:You are given a string s consisting of lowercase English letters, spaces, and exactly one underscore ('_') character. Your task is to reformat the string into a new string in which the underscore character is replaced with a space and all words (sequences of lowercase letters) are reversed, while their positions remain unchanged. Input The first line of input contains a single string s (2 le |s| le 100), containing exactly one underscore character and at least one space. Output Print the reformatted string. Example Input: hello_world this is coding Output: olleh drowthis si gnidoc

answer:def reformat_string(s): Reformats the string by replacing the underscore with a space and reversing all the words. Args: s (str): Input string containing lowercase letters, spaces, and exactly one underscore. Returns: str: Reformatted string. # Replace the underscore with a space s = s.replace('_', ' ') # Split the string by spaces to get individual words words = s.split() # Reverse each word and join them back with spaces reversed_words = ' '.join(word[::-1] for word in words) return reversed_words

question:Anna is organizing a programming competition and wants to create balanced teams. Each participant has a skill level, and Anna needs to divide them into two teams such that the difference in the total skill levels of the teams is minimized. You are given an array `skills` of size `n` where `skills[i]` represents the skill level of the `i`-th participant. Write a function `divideTeams` that divides the participants into two teams and returns the minimum possible difference in the total skill levels of the two teams. The first line contains one integer `t` (`1 <= t <= 1000`) — the number of test cases. Then `t` test cases follow. The first line of each test case contains one integer `n` (`1 <= n <= 100`) — the number of participants. The second line contains `n` integers `skills[1], skills[2], ..., skills[n]` (`1 <= skills[i] <= 1000`) — the skill levels of the participants. For each test case, print one integer — the minimum possible difference in the total skill levels of the two teams. # Example ``` Input: 2 4 1 5 11 5 3 1 2 3 Output: 0 0 ``` # Constraints - The sum of `n` over all test cases does not exceed `1000`. # Note: In the first test case, one optimal way to divide the participants is into teams with skill levels `{1, 5, 5}` and `{11}`, which have the total skill levels of `11` and `11`, respectively. Thus, the difference is `0`. In the second test case, one optimal way to divide the participants is into teams with skill levels `{1, 2}` and `{3}`, which have the total skill levels of `3` and `3`, respectively. Thus, the difference is `0`.

answer:def divideTeams(t, test_cases): def min_difference(skills): total_sum = sum(skills) n = len(skills) dp = [[0] * (total_sum // 2 + 1) for _ in range(n + 1)] for i in range(1, n + 1): for j in range(1, total_sum // 2 + 1): if skills[i - 1] <= j: dp[i][j] = max(dp[i - 1][j], dp[i - 1][j - skills[i - 1]] + skills[i - 1]) else: dp[i][j] = dp[i - 1][j] sum1 = dp[n][total_sum // 2] sum2 = total_sum - sum1 return abs(sum1 - sum2) results = [] for i in range(t): n, skills = test_cases[i] result = min_difference(skills) results.append(result) return results # Example usage: # t = 2 # test_cases = [(4, [1, 5, 11, 5]), (3, [1, 2, 3])] # print(divideTeams(t, test_cases)) # Output: [0, 0]

question:Lucy's Birthday is approaching, and she wants to organize an event at her home. She has m friends, each of whom wants to bring a certain item to the party. Lucy's house, unfortunately, can only accommodate a limited number of items due to space constraints. Each friend i (1 ≤ i ≤ m) can bring k_i items, and each item is uniquely identified by an integer identifier. Lucy's house can only store at most s distinct items, but even if an item is brought by multiple friends, it should only be counted once. Help Lucy determine the maximum number of distinct items she can have at her party. The first line of the input contains two integers m and s (1 ≤ m ≤ 100, 1 ≤ s ≤ 100), the number of friends and the maximum number of distinct items Lucy's house can accommodate. The next m lines describe the items each friend wants to bring. The i-th line starts with an integer k_i (1 ≤ k_i ≤ 100), the number of items friend i wants to bring. Following are k_i integers separated by spaces, representing the identifiers of the items that friend i wants to bring. Print a single integer, the maximum number of distinct items Lucy can have at her party. # Example Input: ``` 3 5 4 1 2 3 4 3 2 3 5 2 1 5 ``` Output: ``` 5 ``` In this example, Lucy can have items 1, 2, 3, 4, and 5 at the party. Even though some items are brought by multiple friends, each item is counted only once.

answer:def max_distinct_items(m, s, friends_items): Returns the maximum number of distinct items Lucy can have at her party. Parameters: m (int): Number of friends s (int): Maximum number of distinct items the house can accommodate friends_items (list of list of int): List of items each friend wants to bring Returns: int: Maximum number of distinct items unique_items = set() for items in friends_items: unique_items.update(items) return min(len(unique_items), s)