answer:class ListNode: def __init__(self, val=0, next=None): self.val = val self.next = next def mergeTwoLists(l1, l2): Merge two sorted linked lists into a single sorted linked list. :param l1: ListNode | None :param l2: ListNode | None :return: ListNode | None dummy = ListNode() # Create a dummy node to simplify the merge process tail = dummy # Tail pointer to keep track of the last node in the merged list while l1 and l2: if l1.val < l2.val: tail.next = l1 l1 = l1.next else: tail.next = l2 l2 = l2.next tail = tail.next # Append the remaining nodes of l1 or l2 if l1: tail.next = l1 if l2: tail.next = l2 return dummy.next # The head of the merged linked list is next of the dummy node

answer:from datetime import datetime def parse_datetime(date_str): Parses a string representing a date and time in various valid formats and returns it as a standardized datetime object. The output format is always "YYYY-MM-DD HH:MM:SS". formats = [ "%Y-%m-%d", "%m/%d/%Y", "%d-%m-%Y %H:%M", "%B %d, %Y" # Add more formats as needed ] for fmt in formats: try: parsed_date = datetime.strptime(date_str, fmt) # If time is not included in the format, we add it manually if "%H" not in fmt: parsed_date = parsed_date.replace(hour=0, minute=0, second=0) return parsed_date.strftime("%Y-%m-%d %H:%M:%S") except ValueError: continue raise ValueError("Date format not recognized. Please use a valid date format.")

answer:def update_inventory(inventory, sold): Updates the inventory based on the items sold. Parameters: inventory (dict): A dictionary containing the current inventory of fruits. sold (dict): A dictionary containing the amount of fruit sold. Returns: dict: The updated inventory of fruits. updated_inventory = inventory.copy() for fruit, amount_sold in sold.items(): # If the fruit is in inventory, subtract the sold amount, but ensure it doesn't go negative if fruit in updated_inventory: updated_inventory[fruit] = max(0, updated_inventory[fruit] - amount_sold) # If the fruit is not in inventory, add it with a negative value indicating the sold amount else: updated_inventory[fruit] = max(0, -amount_sold) return updated_inventory

answer:def merge_sorted_arrays(arr1, arr2): Merges two sorted arrays into a single sorted array. Note: The input arrays should be sorted in non-decreasing order. Parameters: arr1 (List[int]): The first sorted array. arr2 (List[int]): The second sorted array. Returns: List[int]: A merged sorted array. merged_array = [] i = j = 0 while i < len(arr1) and j < len(arr2): if arr1[i] < arr2[j]: merged_array.append(arr1[i]) i += 1 else: merged_array.append(arr2[j]) j += 1 # Append the remaining elements of arr1, if any. while i < len(arr1): merged_array.append(arr1[i]) i += 1 # Append the remaining elements of arr2, if any. while j < len(arr2): merged_array.append(arr2[j]) j += 1 return merged_array