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question:import cv2 import numpy as np import matplotlib.pyplot as plt cap = cv2.VideoCapture(0) cv2.namedWindow("original", cv2.WINDOW_NORMAL) # Define a callback function for mouse event def do_something(event, x, y, flags, params): print("click performed at:", x, y) print("flags: ", flags) # Create a drawing window and set callback for mouse click. cv2.setMouseCallback("original", do_something) if __name__ == "__main__": while cap.isOpened(): ret, frame = cap.read() if not ret: break cv2.imshow("original", frame) if cv2.waitKey(1) & 0xFF == ord('q'): break # When everything done, release the capture cap.release() cv2.destroyAllWindows() In the code above, a mouse click event prints the coordinates of the mouse click, but how do I change the code above to display a circle at the user clicked position on the live video feed?

answer:import cv2 import numpy as np import matplotlib.pyplot as plt # Initialize a list to store the coordinates of the clicked positions clicked_points = [] # Define a callback function for mouse event def do_something(event, x, y, flags, params): if event == cv2.EVENT_LBUTTONDOWN: print("click performed at:", x, y) clicked_points.append((x, y)) # Store the clicked coordinates if __name__ == "__main__": cap = cv2.VideoCapture(0) cv2.namedWindow("original", cv2.WINDOW_NORMAL) # Create a drawing window and set callback for mouse click. cv2.setMouseCallback("original", do_something) while cap.isOpened(): ret, frame = cap.read() if not ret: break # Draw all stored points as circles on the frame for point in clicked_points: cv2.circle(frame, point, 5, (0, 0, 255), -1) cv2.imshow("original", frame) if cv2.waitKey(1) & 0xFF == ord('q'): break # When everything done, release the capture cap.release() cv2.destroyAllWindows()

question:import heapq from collections import deque def min_number_in_piles(piles): min_piles = [pile[0] for pile in piles] heapq.heapify(min_piles) last = 0 while min_piles: ans = heapq.heappop(min_piles) if last == ans: for i, pile in enumerate(piles): if pile[0] == ans: if len(pile) > 1: heapq.heappush(min_piles, pile.popleft()) else: piles.remove(pile) break if ans in pile: i = pile.index(ans) if i != len(pile) - 1: heapq.heappush(min_piles, pile[i + 1]) else: del piles[i] last = ans return len(piles) piles = [list(map(int, input().split())) for _ in range(int(input()))] print(min_number_in_piles(piles)) Now in this problem I want to put the dequeued elements and their frequencies into the minheap. How to do this?

answer:import heapq from collections import deque, defaultdict def min_number_in_piles(piles): min_piles = [(pile[0], i, 0) for i, pile in enumerate(piles)] heapq.heapify(min_piles) element_freq = defaultdict(int) while min_piles: ans, pile_idx, element_idx = heapq.heappop(min_piles) element_freq[ans] += 1 if element_idx + 1 < len(piles[pile_idx]): new_element = piles[pile_idx][element_idx + 1] heapq.heappush(min_piles, (new_element, pile_idx, element_idx + 1)) else: piles[pile_idx] = [] return min_piles, element_freq # Example usage: piles = [ [3, 10, 15, 24], [2, 6, 14, 20], [5, 15, 20, 30] ] # Convert the inner lists to deques piles = [deque(pile) for pile in piles] print(min_number_in_piles(piles))

question:import re import math def parseMolecule(formula): atoms = {} i, n = 0, len(formula) def parse(): nonlocal i, atoms if i == n: return '' c, count = parseAtom() while i < n and formula[i] in '()': if formula[i] == ')': i += 1 mult = parseNumber() count *= mult else: i += 1 tokens = parse() if tokens in atoms: atoms[tokens] += count else: atoms[tokens] = count if i < n and formula[i].isdigit(): mult = parseNumber() count *= mult return c or '' def parseAtom(): nonlocal i if i == n: return '', 1 match = re.match('[A-Z][a-z]?

answer:import re def parseMolecule(formula): atoms = {} stack = [{}] i, n = 0, len(formula) while i < n: if formula[i] == '(' or formula[i] == '[' or formula[i] == '{': stack.append({}) i += 1 elif formula[i] == ')' or formula[i] == ']' or formula[i] == '}': top = stack.pop() i += 1 start = i while i < n and formula[i].isdigit(): i += 1 multiplier = int(formula[start:i] or '1') for k, v in top.items(): if k in stack[-1]: stack[-1][k] += v * multiplier else: stack[-1][k] = v * multiplier else: match = re.match(r'([A-Z][a-z]?)(d*)', formula[i:]) if match: elem = match.group(1) count = int(match.group(2) or '1') if elem in stack[-1]: stack[-1][elem] += count else: stack[-1][elem] = count i += len(match.group(0)) for k, v in stack[0].items(): if k in atoms: atoms[k] += v else: atoms[k] = v return atoms

question:Write a Python solution for Project Euler problem 52. Problem statement: It can be seen that the number, 125874, and its double, 251748, contain exactly the same digits, but in a different order. Find the first even number (not less than 10,000,000) such that, if we take this number multiplied by 2, 3, 4, 5 and 6, we get a number with the same set of digits as the original number.

answer:def has_same_digits(x, y): return sorted(str(x)) == sorted(str(y)) def find_special_number(): num = 10000000 while True: if (num % 2 == 0 and has_same_digits(num, num * 2) and has_same_digits(num, num * 3) and has_same_digits(num, num * 4) and has_same_digits(num, num * 5) and has_same_digits(num, num * 6)): return num num += 2 # Increment by 2 to ensure the number remains even