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question:def maximal_positions_match(n: int, s: str, t: str) -> int: You are given two strings s and t. Vasya can rearrange (permute) the characters of string s. He wants to do it in such a way that the number of positions in the rearranged string s where the characters match the characters in string t is maximized. Help Vasya find the maximal number of matches possible. Args: n: the length of strings s and t. s: the string s consisting of lowercase English letters. t: the string t consisting of lowercase English letters. Returns: The maximal number of positions in the rearranged string s that can match the characters in string t. Example: >>> maximal_positions_match(4, 'aabc', 'cbda') 3 >>> maximal_positions_match(3, 'abc', 'xyz') 0
answer:from collections import Counter def maximal_positions_match(n, s, t): Returns the maximum number of positions where characters of rearranged string s match string t. s_count = Counter(s) t_count = Counter(t) matches = 0 for char in t_count: if char in s_count: matches += min(s_count[char], t_count[char]) return matches
question:def robHouses(nums): Given an array of n integers representing the amount of money at each house, determine the maximum amount of money the thief can rob without triggering the alarm. The houses are arranged in a circle, and the thief cannot rob consecutive houses. Examples: >>> robHouses([2, 3, 2]) 3 >>> robHouses([1, 2, 3, 1]) 4 >>> robHouses([1, 2, 3]) 3
answer:def robHouses(nums): if len(nums) == 1: return nums[0] return max(rob_linear(nums[:-1]), rob_linear(nums[1:])) def rob_linear(nums): prev, curr = 0, 0 for num in nums: prev, curr = curr, max(curr, prev + num) return curr
question:from typing import List import string def most_common_words(text: str) -> List[str]: Returns the list of most common words in alphabetical order after removing punctuation and converting to lowercase. >>> text1 = "Hello, hello? HELLO! How are you you you?" >>> most_common_words(text1) ["hello", "you"] >>> text2 = "It was the best of times, it was the worst of times." >>> most_common_words(text2) ["it", "of", "the", "times", "was"] pass
answer:from typing import List import string from collections import Counter def most_common_words(text: str) -> List[str]: Returns the list of most common words in alphabetical order after removing punctuation and converting to lowercase. # Remove punctuation translator = str.maketrans('', '', string.punctuation) cleaned_text = text.translate(translator) # Convert to lowercase and split into words words = cleaned_text.lower().split() # Count word frequencies word_counts = Counter(words) # Find the highest frequency max_count = max(word_counts.values()) # Extract words with the highest frequency most_common = [word for word, count in word_counts.items() if count == max_count] # Return the words sorted alphabetically return sorted(most_common)
question:def min_coins(t: int, cases: List[int]) -> List[int]: Determine the minimum number of coins needed to make any given amount of change using denominations of 1, 3, and 4 cents. Input: t (int): number of test cases cases (List[int]): the list of amounts of change to be made Output: List[int]: a list of integers representing the minimum number of coins needed for each amount Examples: >>> min_coins(3, [6, 11, 15]) [2, 3, 4] >>> min_coins(1, [1]) [1] >>> min_coins(1, [4]) [1] >>> min_coins(1, [3]) [1] >>> min_coins(1, [10]) [3] >>> min_coins(1, [0]) [0] >>> min_coins(1, [10000]) [2500] >>> min_coins(5, [1, 2, 3, 4, 5]) [1, 2, 1, 1, 2] >>> min_coins(3, [7, 9, 12]) [2, 3, 3] >>> min_coins(1, [9999]) [2500]
answer:def min_coins(t, cases): Returns the minimum number of coins needed to make the given amounts of change for each case. :param t: Number of test cases :param cases: A list of integers where each integer represents an amount of change to be made :return: A list of integers where each integer represents the minimum number of coins needed for the corresponding amount in cases max_amount = max(cases) # Initialize a list to store the minimum number of coins for each amount up to the maximum amount in the cases min_coins_required = [float('inf')] * (max_amount + 1) # Base case: 0 coins needed to make 0 cents min_coins_required[0] = 0 denominations = [1, 3, 4] for i in range(1, max_amount + 1): for coin in denominations: if i >= coin: min_coins_required[i] = min(min_coins_required[i], min_coins_required[i - coin] + 1) result = [min_coins_required[amount] for amount in cases] return result