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question:def can_be_transformed_to_palindrome(s: str) -> str: Determines if a string containing only characters 'a', 'b', and 'c' can be transformed into a palindrome by rearranging its characters and optionally changing at most one character. >>> can_be_transformed_to_palindrome("abac") == "YES" >>> can_be_transformed_to_palindrome("aaabc") == "NO" >>> can_be_transformed_to_palindrome("aabbcc") == "YES" from collections import Counter # Unit tests def test_example_cases(): assert can_be_transformed_to_palindrome("abac") == "YES" assert can_be_transformed_to_palindrome("aaabc") == "NO" assert can_be_transformed_to_palindrome("aabbcc") == "YES" def test_empty_string(): assert can_be_transformed_to_palindrome("") == "YES" # Trivially a palindrome def test_single_character(): assert can_be_transformed_to_palindrome("a") == "YES" assert can_be_transformed_to_palindrome("b") == "YES" assert can_be_transformed_to_palindrome("c") == "YES" def test_all_identical_characters(): assert can_be_transformed_to_palindrome("aaa") == "YES" assert can_be_transformed_to_palindrome("bbbb") == "YES" assert can_be_transformed_to_palindrome("ccccc") == "YES" def test_multiple_odd_counts(): assert can_be_transformed_to_palindrome("abcabcabc") == "NO" # 3 'a's, 3 'b's, 3 'c's def test_edge_cases(): assert can_be_transformed_to_palindrome("aabb") == "YES" assert can_be_transformed_to_palindrome("aabbc") == "YES" assert can_be_transformed_to_palindrome("aabbb") == "YES" def test_complex_case(): assert can_be_transformed_to_palindrome("aabcaa") == "YES" # Can make one substitution and rearrange to form a palindrome
answer:def can_be_transformed_to_palindrome(s): Determines if a string containing only characters 'a', 'b', and 'c' can be transformed into a palindrome by rearranging its characters and optionally changing at most one character. from collections import Counter char_count = Counter(s) odd_count = sum(1 for count in char_count.values() if count % 2 == 1) # A string can be transformed into a palindrome if there is at most one odd-count character. if odd_count <= 1: return "YES" # If there are exactly two odd-count characters, we can still make one change to make the string a palindrome. elif odd_count == 2: return "YES" else: return "NO"
question:def can_be_grouped_into_pairs(N: int, S: str) -> str: Returns 'Yes' if the gems can be grouped into pairs of the same color, otherwise 'No'. >>> can_be_grouped_into_pairs(6, 'RGBRGB') 'Yes' >>> can_be_grouped_into_pairs(5, 'RRGBG') 'No' >>> can_be_grouped_into_pairs(8, 'RRGGBBYY') 'Yes'
answer:def can_be_grouped_into_pairs(N, S): Returns 'Yes' if the gems can be grouped into pairs of the same color, otherwise 'No'. from collections import Counter # Count the frequency of each color color_count = Counter(S) # Check if all counts are even for count in color_count.values(): if count % 2 != 0: return 'No' return 'Yes'
question:def process_input(input_string: str) -> int: Process the input string according to the specified rules: - Sum the digits in the string. - Adjust the sum based on the first character: * Add 1 if the first character is 'A'. * Subtract 1 if the first character is 'B'. * Double the sum if the first character is 'C'. * Halve the sum if the first character is 'D'. >>> process_input("A-12345678") == 37 >>> process_input("B-87654321") == 35 >>> process_input("C-12345678") == 72 >>> process_input("D-87654321") == 18 >>> process_input("A-11111111") == 9 >>> process_input("C-00000000") == 0 >>> process_input("D-00000000") == 0
answer:def process_input(input_string): Process the input string according to the specified rules: - Sum the digits in the string. - Adjust the sum based on the first character: * Add 1 if the first character is 'A'. * Subtract 1 if the first character is 'B'. * Double the sum if the first character is 'C'. * Halve the sum if the first character is 'D'. first_character = input_string[0] digits = input_string[2:] total_sum = sum(int(digit) for digit in digits) if first_character == 'A': total_sum += 1 elif first_character == 'B': total_sum -= 1 elif first_character == 'C': total_sum *= 2 elif first_character == 'D': total_sum //= 2 return total_sum
question:def find_latest_version(versions: List[str]) -> str: Finds and returns the latest version among a list of versions. >>> find_latest_version(["1.2.3", "1.3.0", "1.2.10"]) "1.3.0" >>> find_latest_version(["1.2.3", "1.2.4", "1.2.2"]) "1.2.4" >>> find_latest_version(["1.2.3", "2.0.0", "1.4.5"]) "2.0.0" >>> find_latest_version(["1.0.0", "1.0.0", "1.0.0"]) "1.0.0" >>> find_latest_version(["0.0.1"]) "0.0.1"
answer:def find_latest_version(versions): Finds and returns the latest version among a list of versions. Args: versions (list of str): A list of version strings in the format "Major.Minor.Patch". Returns: str: The latest version string. return max(versions, key=lambda v: list(map(int, v.split('.'))))