Appearance
question:In this problem, you are given a sequence of n integers representing the heights of n buildings in a row. You need to determine the maximum area of a rectangle that can be formed by choosing consecutive buildings. The area of a rectangle is determined by the height of the shortest building in the chosen sequence and the number of buildings in that sequence. The first line contains a single integer n (1 ≤ n ≤ 500,000), representing the number of buildings. The second line contains n integers h1, h2, ..., hn (1 ≤ hi ≤ 100,000), representing the heights of the buildings. Output a single integer — the maximum area of a rectangle that can be formed by choosing consecutive buildings. Example: Input: 5 2 1 5 6 2 Output: 10 In this example, the maximum rectangular area is obtained by choosing the third and fourth buildings with heights 5 and 6, resulting in an area of 5 * 2 = 10.
answer:def largest_rectangle_area(heights): Return the maximum area of a rectangle that can be formed by choosing consecutive buildings. Args: heights (list of int): List of building heights. Returns: int: Maximum area of rectangle. stack = [] max_area = 0 index = 0 while index < len(heights): if not stack or heights[stack[-1]] <= heights[index]: stack.append(index) index += 1 else: top_of_stack = stack.pop() area = (heights[top_of_stack] * ((index - stack[-1] - 1) if stack else index)) max_area = max(max_area, area) while stack: top_of_stack = stack.pop() area = (heights[top_of_stack] * ((index - stack[-1] - 1) if stack else index)) max_area = max(max_area, area) return max_area
question:Maurice is participating in a game where he is required to collect specific items in a particular order to progress. Each item is represented by a unique integer. Maurice has a backpack with a limited capacity and each item has a specific weight. Given a list of items Maurice is required to collect, their weights, and the maximum capacity of the backpack, determine if it is possible for Maurice to carry all required items in the backpack at once. If it is possible, print "YES". Otherwise, print "NO". The first line contains two space-separated integers n (1 ≤ n ≤ 100) — the number of items Maurice needs to collect, and W (1 ≤ W ≤ 10^9) — the maximum capacity of the backpack. The second line contains n space-separated integers wi (1 ≤ wi ≤ 10^8) — the weights of the items Maurice needs to collect. Print a single line with "YES" if Maurice can carry all items in his backpack, otherwise print "NO". For example: In the first sample, the sum of weights 1 + 2 + 3 = 6 is less than the maximum capacity 10, so the output is "YES". In the second sample, the sum of weights 5 + 5 + 5 = 15 exceeds the maximum capacity 12, so the output is "NO".
answer:def can_carry_all_items(n, W, weights): Determines if Maurice can carry all required items in his backpack given the weights and capacity. Parameters: n (int): Number of items. W (int): Maximum capacity of the backpack. weights (list of int): Weights of the items. Returns: str: "YES" if Maurice can carry all items, otherwise "NO". if sum(weights) <= W: return "YES" else: return "NO"
question:A convoy of trucks has to deliver resources to a remote base and there is a single road which can be traversed once. Each truck can carry a different amount of resources but the road cannot handle too much load at once. To optimize the delivery, you need to maximize the total resources delivered without exceeding the road's capacity limit. You are given the maximum capacity of the road, the number of trucks, and the resource capacity of each truck. Your task is to determine the maximum amount of resources that can be delivered using any combination of trucks such that their combined resource capacity does not exceed the maximum capacity of the road. # Input - The first line contains two integers `C` and `n` (1 ≤ C ≤ 10^5, 1 ≤ n ≤ 100), where `C` is the maximum capacity of the road and `n` is the number of trucks. - The second line contains `n` space-separated integers `a1, a2, ..., an` (1 ≤ ai ≤ 10^4), where `ai` is the resource capacity of the i-th truck. # Output - Print a single integer, the maximum total resources that can be delivered without exceeding the road's capacity. # Example Input ``` 50 5 10 20 30 40 50 ``` Output ``` 50 ``` Input ``` 60 5 15 25 35 45 55 ``` Output ``` 60 ```
answer:def max_resources(C, n, capacities): dp = [0] * (C + 1) for cap in capacities: for i in range(C, cap - 1, -1): dp[i] = max(dp[i], dp[i - cap] + cap) return dp[C] if __name__ == "__main__": import sys input = sys.stdin.read data = input().split() C = int(data[0]) n = int(data[1]) capacities = list(map(int, data[2:2+n])) print(max_resources(C, n, capacities))
question:Given a string `s` consisting of lowercase alphabets, you need to determine the lexicographically smallest string that can be obtained by removing any one character from the string. The first line contains an integer `t` (1 ≤ t ≤ 100) — the number of test cases. Each of the next `t` lines contains a string `s` (1 ≤ |s| ≤ 100). For each test case, print a single line containing the lexicographically smallest string obtainable after removing exactly one character from `s`. # Example Input ``` 3 abc acb cba ``` Output ``` ab ab ba ``` # Explanation - For the first test case, removing 'c' results in "ab", 'b' results in "ac", and 'a' results in "bc". Among them, "ab" is the smallest lexicographically. - For the second test case, removing 'b' or 'c' both result in "ac", which is the smallest. - For the third test case, removing 'c' results in "ba" which is the smallest.
answer:def lexicographically_smallest_string(s): Returns the lexicographically smallest string that can be obtained by removing one character from s. smallest_string = s[1:] # Initial smallest string by removing the first character for i in range(1, len(s)): new_string = s[:i] + s[i+1:] # Remove one character at position i if new_string < smallest_string: smallest_string = new_string return smallest_string def process_test_cases(test_cases): Processes multiple test cases and returns the results. results = [] for s in test_cases: result = lexicographically_smallest_string(s) results.append(result) return results